The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. what does the average rate of change of d(t) from t = 2 to t = 5 represent?

Answer

Find out what does the average rate of change of d(t) from t = 2 to t = 5 represent .

To prove

Formula

As given

The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t²

 where d equals the distance traveled at time t seconds .

Now

d(5) = 16 × 5 × 5

      = 400 feet

d(2) = 16 × 2 × 2

      = 64 feet

Now

Change in time = 5 - 2

                          = 3 second

put all the values in the above formula

Average rate of change is 112 feet/second.

The average rate of change of height is speed.

The average rate of change of d(t) on t ∈ [2, 5] represents the ball's average speed over that interval of time.

answer is because 4×10=40

and 98×4= is 392

40,392