The length of a rectangle is 9 centimeters less than the width. what are the dimensions of the rectangle if it’s area is 162 square centimeters

Let w = the width of the rectangle

Let w - 9 = the length of the rectangle

A = lw

220 = w(w - 9)

220 = w2 - 9w

w2 - 9w - 220 = 0

(w - 20)(w + 11) = 0

w - 20 = 0     or     w + 11 = 0

w = 20 cm    or     x = -11, illogical answer

w - 9 = 20 - 9 = 11 cm

Step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer