The length of a rectangle is 2m more that it's width. The perimeter is 60m. What is its width?

The width is 14m

Step-by-step explanation: The question has provided the perimeter as 60. The available clues are such that the length measures 2m more than it's width. This means whatever is the width of the rectangle, the length shall be equal to plus 2. Hence, if the width is W, the length is W + 2.

So we have,

Perimeter = 60

Length = W + 2 and

Width = W

Already the perimeter is given as

Perimeter = 2(L + W)

We can now express the perimeter as follows;

60 = 2(W + 2 + W)

60 = 2(2 + 2W)

By cross multiplication we now have

60/2 = 2 + 2W

30 = 2 + 2W

Subtract 2 from both sides of the equation

28 = 2W

Divide both sides of the equation by 2

14 = W.

Remember that the length is given as W + 2, so the length becomes

14 + 2 = 16

Therefore, the width equals 14 m.

Step-by-step explanation:

Width = x

Length = x +2

Perimeter = 60 m

2*(length + width) = 60

2*(x + 2 + x) = 60

2*(2x + 2) = 60

    2x + 2 = 60/2

    2x + 2 = 30

          2x = 30-2

          2x = 28

           x = 28/2

          x = 14

Width = 14 m

Length = 14+ 2 = 16 m

good luck!

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