One number is 20 greater than another. If the lesser is subtracted from three times the greater number, the difference is 84. Find the number.

X=32 and Y=12

The two numbers are 32 and 12

Step-by-step explanation:

Let the number be represented by X and Y

X = 20 + Y equation 1

3X - Y = 84 equation 2

solving the equation by substitution;

we substitute equation 1 into equation 2, we have;

3(20+Y)-Y = 84

expanding the bracket;

60 + 3Y - Y = 84

60 + 2Y = 84

2Y = 84 - 60

2Y = 24

divide both sides by 2;

2Y/2 = 24/2

Y = 12

from equation 1, we can find X by using the value of Y;

X = 20 + Y

X = 20 + 12

X = 32

PROOF:

using equation 2;

[3*32]-12=84

96-12=84

84=84

i have no answer for this maybe o 7 units