Evaluate 5c+cd when c=1/5 and d = 15

4

Step-by-step explanation: Here we're asked to evaluate 5c + cd given that c = 1/5 and d = 15.

So all we have to do is plug our given values for c and d into the problem and simplify from there.

5c would be 5(1/5) + c which is 1/5 · d which is 15 so we have (1/5)(15).

So rewriting our problem we have 5(1/5) + (1/5)(15).

Simplifying from here, remember that our order of operations tells us we must first multiply 5(1/5) and (1/5)(15).

So multiplying 5(1/5), the 5 and 5 cross cancel

to 1 and 1 so we have 1 · 1 or 1.

Next we have (1/5)(15) which we can rewrite as

(1/5)(15/1) which is 15/5 or 3.

So we now have 1 + 3 which is 4.

0/5 is 0, 2/0 is undefined, and 0/0 is indeterminate.

step-by-step explanation:

hope my answer has you!

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)