Math school is selling tickets to a play on the first day of ticket sales the school sold two adult tickets and three students tickets for a total of $57 the school took and $70 on the second day by selling two adult tickets and four student tickets what is the price each of one adult ticket and one student ticket

the cost of an adult ticket is $9.

The cost of a child's ticket is $13

Step-by-step explanation:

Let x represent the price of one adult ticket.

Let y represent the price of one student ticket.

On the first day of ticket sales, the school sold two adult tickets and three students tickets for a total of $57. It means that

2x + 3y = 57- - - - - - - - - -1

The school took and $70 on the second day by selling two adult tickets and four student tickets. It means that

2x + 4y = 70- - - - - - - - - -2

Subtracting equation 2 from equation 1, it becomes

- y = - 13

y = 13

Substituting y = 13 into equation 1, it becomes

2x + 3 × 13 = 57

2x + 39 = 57

2x = 57 - 39 = 18

x = 18/2

x = 9

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step-by-step explanation:

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: