Solve the system of linear equations by substitution.

−x−8=−y
9y−12+3x=0

The solution is ( , )

The solution (x, y) = (-5, 3)

Step-by-step explanation:

-x - 8 = -y (1)

9y - 12 + 3x = 0 (2)

from equation (1)

-x = - y + 8 ... (3)

multiply equation (3) by -1

x = y - 8 (4)

substituting equation (4) in equation (2)

9y - 12 + 3 ( y - 8) = 0

9y - 12 + 3y - 24 = 0

12y - 36 = 0

12y = 36

y = 36 /12

y = 3

Substitute y = 3 in equation (4)

x = y - 8

x = 3 - 8

x = -5

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

i think it is 70

step-by-step explanation: