The vertices of / are q(–4,0), p(–6, 7), and r(–2, 1). / is rotated 90° counterclockwise about the origin to form /. what are the coordinates of the vertices of /?

The vertices of coordinates of image are Q'(0,-4), P'(-7,-6) and R'(-1,-2).

Step-by-step explanation:

The vertices of triangle QPR are Q(–4,0), P(–6, 7), and R(–2, 1). It is rotated 90° counterclockwise about the origin to form a new triangle Q'P'R'.

If a figure rotated 90° counterclockwise about the origin, then

The coordinated of image are

Therefore the vertices of coordinates of image are Q'(0,-4), P'(-7,-6) and R'(-1,-2).

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1