Both Mr. flores and Mrs. Duncan have the same math test to their classes. The results are in the tables shown. Mr. Flores 92 87 61 82 98 100 77 64 85 93 92 87 100 93 90 Mrs. Duncan 82 85 91 76 79 82 95 56 95 89 88 64 69 78 88
a. Calculate the range for each class’ test scores.
b. Compare the mean for each class’ test scores.

range for mr Flore's test = 39

Range for mrs Duncan's test scores = 39

b) Mean of Flore's test scores= 86.7

Mean of Mrs. Duncan's test scores = 81.1

The mean of test scores of mr Flore's test scores is greater than the mean test scores of Mrs. Duncan's.

Step-by-step explanation:

Range is calculated by highest number in a data set - lowest number in a data set

Given the data set for Mr. Flores test scores: 92 87 61 82 98 100 77 64 85 93 92 87 100 93 90

Highest value = 100, lowest value = 61

a) Range for mr. Flore's test = 100 - 61 = 39

Given the data set for Mrs. Duncan's test scores: 82 85 91 76 79 82 95 56 95 89 88 64 69 78 88

ii) Range for mrs Duncan's test score= 95-56= 39

b) mean is calculated by total sum of scores/ number of scores

Mean for mr Flore's test scores = 92 +87 +61 +82 +98 +100 +77 +64 +85+ 93 +92 +87 +100 +93 +90 / 15

=1301/15

=86.7

Mean for mrs. Duncan's test scores = 82 +85 +91 +76+ 79 +82 +95 +56+ 95 +89+ 88+ 64+ 69 +78+ 88 / 15

=1217/15

=81.1

I hope this helps.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11