Kala’s company makes solid metal balls for various industrial uses. A customer wants aluminum balls that have a diameter of 6 in. If Kala must make 70 of those balls, how much aluminum will she need?

7,912.8 inch³ of aluminum is needed to make 70 metal balls.

Step-by-step explanation:

Step 1:

The area of a sphere is calculated by multiplying with π and the cube of the radius (r³).

In the given problem, the diameter is 6 inches. So the radius of the spheres is 3 inches.

The volume of a sphere,

So if r = 3 inches and π = 3.14,  

cubic inches.

So for a single aluminum ball, 113.04 inch³ of aluminum is needed.

Step 2:

If 113.04 inch³ of aluminum is used for 1 ball, then we multiply 70 with this value to determine the aluminum needed for 70 such balls.

The aluminum needed for 70 metal balls inch³.

So 7,912.8 inch³ of aluminum is needed to make 70 metal balls.

step-by-step explanation: i dont

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: