Carl puts $1.10 in his penny bank everyday in the moth of July (31 days). His total savings was $55 at the end of June. What is the best estimate for Carl's saving at the end of July?

C) About $85

Step-by-step explanation:

Please consider the complete question.

Carl puts $1.10 in his penny bank every day in the month of July (31 days). His total saving at the end of June is $55.00. What is the best estimate at the end of July?

A) about $25

B) about $115

C) about $85

D) about $66

First of all, we will round $1.10 to nearest whole number and round 31 to nearest tens as:

So amount saved in 30 days would be 30 times $1.

Carl's savings at the end of July would be amount saved in June plus amount saved in July that is

Therefore, the estimate for Carl's saving at the end of July is $85 and option C is the correct choice.

its a straight line parallel to the time axis

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)