Determine the solution for x^2+36>12x

x> 6 twice

Step-by-step explanation:

x^2+36>12x

x² + 36 > 12x

Collect like terms

x² - 12x + 36 > 0

Solve quadratically using factorisation method by finding two factors of 36 that when added gives -12, the coefficient of x.

Factors = -6 and -6 which both add up to -12

Rewrite equation

x² - 6x - 6x +36> 0

Factorise by taking out the common factor

x ( x - 6) -6( x - 6) > 0

(x -6)(x - 6) > 0

x - 6 > 0 or x -6 > 0

Add 6 to both sides

x -6+6> 0+6 or x-6+6>0+6

x > 6  or x> 6

x> 6 twice

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step-by-step explanation:

you put them as all the same denominator and multiply