How so you slove 4^2x-1 = 8^x+2 ?

x =

Step-by-step explanation:

ln both sides like you would add the same number to both sides to keep the equation equivalent

using log rules, exponents can be brought down as a constant multiplying ln

use distributive property to remove parentheses

2xln(4) - ln(4) = xln(8) + 2ln(8)

isolate x

2xln(4) - xln(8) = 2ln(8) + ln(4)

rewrite the logs using log rules: ln(x) - ln(y) = ln() and the exponent rule stated above

xln()-xln(8) = ln()

factor out x

x(ln-ln8) = ln()

again use log rules:  ln(x) - ln(y) = ln()

x* =  ln()

now simplify the stuff inside the ln parentheses

x*ln(2) = ln(16)

x =

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

4th option is correct xy=-10

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