The cabin of a business jet has a cabin height 5 feet 9 inches high. If a business traveler’s height is N(5'10", 2.7"), what percentage of the business travelers will have to stoop? (Round your answer to 4 decimal places.) Probability

0.6443 = 64.43% of the business travelers will have to stoop

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Each feet is 12 inches

So

5'9'' = 5*12 + 9 = 69

5'10'' = 5*12 + 10 = 70

What percentage of the business travelers will have to stoop?

This is 1 subtracted by the pvalue of Z when X = 69. So

has a pvalue of 0.3557.

1 - 0.3557 = 0.6443

0.6443 = 64.43% of the business travelers will have to stoop

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!