Can someone please help me with this question What is the minimum value of the quadratic function f(x) = x² - 2x + 7

minimum value of the quadratic function f(x) = x² - 2x + 7 is at x=1 & is (1, 6).

Step-by-step explanation:

Here we have ,  f(x) = x² - 2x + 7 or . We need to find the minimum value of f(x) for which we need to differentiate it one time and equate it to zero . Value of x at which first differentiation of f(x) is zero will be the minimum value of function  . Let's solve this:

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Now, value of function at x=1 is :

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Therefore, minimum value of the quadratic function f(x) = x² - 2x + 7 is at x=1 & is (1, 6).

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step-by-step explanation:

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y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead