In a fraternity with 40 members , 18 take mathematics, 5 take both mathematics and physics, and 8 take neither mathematics nor physics. How many take physics but not mathematics?

14 members take physics but not mathematics

Step-by-step explanation:

Please see the attached for a diagrammatic representation of this situation.

Since there are 40 members but 8 did not offer any of mathematics or physics, then:-

40 - 8 = 32

So, 32 members of the fraternity offer maths, physics or both.

5 members offer both mathematics and physics .

Since 5 members offer both mathematics and physics, the number of members that offer maths alone = 18 - 5

Let us use "P" to represent the number of members that offer physics. Therefore, the number of members that offer only physics = (P - 5)

Now, if we add up the members that offered maths only, the members that offered both mathematics and physics and the members that offered only physics, it will be equal to the 32 members that offered at least a subject.

Therefore, (18 - 5) + 5 + (P - 5) = 32

18 - 5 + 5 + P - 5 = 32

18 + P - 5 = 32

P + 13 = 32

P = 32 - 13

P = 19

19 members offered physics out of the 32 members that offered maths, physics or both.

To find out the number of people or members that offered physics only, we subtract the number of members that offered the two subjects (5) from a total of 19 members that offered Physics

19 - 5 = 14

Therefore, 14 members of the fraternity offer only physics

b.my answer is b.

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step-by-step explanation: