Look at the figure below:

an image of a right triangle is shown with an angle labeled y

If sin y° = 7 over q and tan y° = 7 over r, what is the value of sec y°?

sec y° = q over r
sec y° = 7r
sec y° = 7q
sec y° = r over q

sec y° = q over r ⇒ 1st answer

Step-by-step explanation:

Let us revise some trigonometry ratios

∵ sin y° =

∵ tan y° =

- Substitute tan(y) by

∴    =

- To find sec y° divide by sin(y)

∵ ÷ sin(y) = ÷

- Change (÷) to (×) and reciprocal the term after (÷)

× = ×

- Simplify the left hand side by divide up and down by sin(y)

   and the right hand side by divide up and down by 7

∴ =  

∵  sec y° =  

∴ sec y° =  

∴ sec y° = q over r

answer: ask

step-by-step explanation:

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)