A hexagonal pyramid that has a slant height of 39 cm and its hexagonal base has a radius of 10√3 cm.
What is the volume of the pyramid?

225

Step-by-step explanation:

Volume of the pyramid is calculated as 1/3 bh, where b is base and h is height

Given height as 39cm and a base of 10√3cm = 10 x √3, where √3= 1.73; base = 10 x 1.73 = 17.3

Slot the values into the formula:

Volume = 1/3 × 17.3 x 39

= 1/3 × 674.7 = 674.7/3

Volume = 224.9 approximately 225.

I hope this helps.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )