Suppose SAT Writing scores are normally distributed with a mean of 498 and a standard deviation of 114. A university plans to award scholarships to students whose scores are in the top 6%. What is the minimum score required for the scholarship? Round your answer to the nearest whole number, if necessary.

the minimum score required for the scholarship is 676.

Step-by-step explanation:

Suppose SAT Writing scores are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = SAT Writing scores.

µ = mean score

σ = standard deviation

From the information given,

µ = 498

σ = 114

The probability value for the scores in the top 6% would be (1 - 6/100) = (1 - 0.06) = 0.94

Looking at the normal distribution table, the z score corresponding to the probability value is 1.56

Therefore,

1.56 = (x - 498)/114

Cross multiplying by 114, it becomes

1.56 × 114 = x - 498

177.84 = x - 498

x = 177.84 + 498

x = 676 rounded to the nearest whole number.

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.