WILL MARK BRAINLIEST
A firework rocket consists of a cone stacked on top of a cylinder, where the radii of the cone and the cylinder are equal. The diameter of the cylindrical base of the rocket is 8 in and the height of the cylinder is 5 in, while the height of the cone is 3 in. Calculate the surface area of the rocket. Leave your answer in terms of π.

184π sq. in.
76π sq. in.
168π sq. in.
88π sq. in.

ANSWER: 76π square inches.

Step-by-step explanation:
The surface area of the shape consist of 3 parts: the circular base, the cylindrical base, and the cone base. So the total surface area will be given by:
Total Surface Area = Area of Circle + Surface Area of Cylindrical Base + Surface Area of Cone.
Area of Circle = π*r^2.
Surface Area of Cylinder (without base) = 2*π*r*h.
Surface Area of Cone (without base) = π*r*sqrt(r^2 + h^2).
Therefore, total area is given by:
Total Surface Area = π*r^2 + 2*π*r*h + π*r*sqrt(r^2 + h^2).
Substitute radius = 4 inches, height of cylinder = 5 inches and height of cone = 3 inches in the above formula.
Total Surface Area = π*4^2 + 2*π*4*5 + π*4*sqrt(4^2 + 3^2).
Total Surface Area = 16π + 40π+ 20π.
Total Surface Area = 76π square inches

A friend helped me, your welcome.