Three vertices of parallelogram JKLM are J(1, 4), K(5, 3), and L(6,−3). Find the coordinates of vertex M.

coordinates of vertex M is (x, y) = (2, -2)

Step-by-step explanation:

Since JKLM is a  parallelogram, this implies that JK parallel to LM and KL parallel to JM. This means that

Slope of JK = slope of LM

And

Slope of KL = slope of JM

From equation (i) and (ii) we get

Put the value of x in equation (ii) we get

So, the coordinates of vertex M is (x, y) = (2, -2).

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.