What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?

Answer Expert Verified x= -8/2+(8^2-2*(-9))^(1/2)/2 and x=-8/2-(8^2-2*(-9))^(1/2)/2; x= -4+ \sqrt{64+18} /2 and x=-4- \sqrt{64+18} /2; x= -4+ \sqrt{\frac{41}{2}} and x= -4- \sqrt{\frac{41}{2}} . f(x)=0, if x= -4+ \sqrt{\frac{41}{2}} and x= -4- \sqrt{\frac{41}{2}} .

Step-by-step explanation:

-1/2 +2

step-by-step explanation:

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm