A squirrel is 24 feet up in a tree and tosses a nut out of the tree with an initial velocity of 8 feet per second. The nuts height, h, at time t seconds can be represented by the equation h(t)=-16t^2 + 8t +24. If the squirrel climbs down the tree in 2 seconds, does it reach the ground before the nut?

Therefore,

Yes , Nut reaches faster than squirrel  by half second.

Step-by-step explanation:

The nuts height,h, at time t seconds can be represented by the equation

To Find:

If the squirrel climbs down the tree in 2 seconds, does it reach the ground before the nut = ?

Solution:

For nut to reach the ground, Put h(t) = 0

Dividing through out by 8 we get

Factorizing we get

As time cannot be negative

t = 1.5 seconds nut reaches at ground.

The squirrel climbs down the tree in 2 seconds .....Given

Difference of time = 2 - 1.5 = 0.5 second

Therefore,

Yes , Nut reaches faster than squirrel  by half second.

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get