Transpose then formula

F = (9/5)C + 32

So that C is the subject of the equation.

C = F - 32 /(9/5)

Step-by-step explanation:

F = (9/5)C + 32

Subtract 32 from both sides

F - 32 = (9/5)C + 32 - 32

F - 32 = (9/5)C

Divide both sides by (9/5)

F - 32/(9/5) = (9/5)C/(9/5)

F - 32/(9/5) = C

C = F - 32 /(9/5)

F = (9/5)C+32

C= (F-32)*(5/9)

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

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step-by-step explanation: