What is the maximum value of h(t)=−16t^2+32t+64

Step-by-step explanation:

h(t)=-16t²+32t+64

=-16(t²-2t)+64

=-16(t²-2t+1-1)+64

=-16(t-1)²+16+64

=-16(t-1)²+80

maximum value=80 and is obtained at t=1

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval