Find the zeros of y= x2 - 4x - 9 by completing the square.
Ο Α. x = 24/13
Β. χ = 3! 13
Ο
Ο
C. = 43
Ο
Ο D. χ = -2 + 13

A

Step-by-step explanation:

To find the zeros equate y to zero, that is

x² - 4x - 9 = 0 ( add 9 to both sides )

x² - 4x = 9

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 2)x + 4 = 9 + 4

(x - 2)² = 13 ( take the square root of both sides )

x - 2 = ± ( add 2 to both sides )

x = 2 ± → A

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3