American Airlines flights from Dallas to Chicago are on-time 80% of the time. Suppose 15 flights are randomly selected, and the number of on-time flights is recorded. Find and the probability that exactly 10 flights are on time.

Probability that exactly 10 flights are on time is 0.1032.

Step-by-step explanation:

We are given that American Airlines flights from Dallas to Chicago are on-time 80% of the time. Suppose 15 flights are randomly selected, and the number of on-time flights is recorded.

The above situation can be represented through Binomial distribution;

where, n = number of trials (samples) taken = 15 flights

           r = number of success

           p = probability of success which in our question is % of flights that   

                 are on time, i.e., 80%

LET X = Number of flights that are on time

Also, it is given that a sample of 15 flights is taken,

So, it means X ~

So, Probability that exactly 10 flights are on time = P(X = 10)

P(X = 10) =

              =

              = 0.1032

Therefore, Probability that exactly 10 flights are on time is 0.1032.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*