Circle B with center B(0, 2) that passes through (6, 0)

(

( x - 0)^2 + (y - 2)^2 = 40

Step-by-step explanation:

We are asked to find the equation of a circle

Step 1: find the radius

( x - a) ^2 + ( y - b) ^2 = r^2

(a, b) - center of the circle

(x, y) - any point on the circle

r^2 - radius of the circle

Using the center

( a, b) = ( 0 , 2)

(x , y) = (6 , 0)

(a, b) = (0 , 2)

a = 0

b = 2

Inserting the values given into the equation

( x - a)^2 + ( y - b) ^2 = r^2

( x - 0)^2 + (y - 2)^2 = r^2

Step 2: sub (x, y) = ( 6 , 0)

x = 6

y = 0

( 6 - 0)^2 + ( 0 - 2)^2 = r^2

6^2 + (-2)^2 = r^2

36 + 4 = r^2

40 = r^2

Step 3: sub the radius into the equation

(x - 0)^2 + ( y -2)^2 = r^2

( x - 0)^2 + (y - 2)^2 = 40

The equation of the circle is

( x - 0)^2 + ( y - 2)^2 = 40

i think the answer is fried chicken ; >

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph