A new car is purchased for $36000 and over it's value depreciates by 1/2 every five years. What is the value of the car 17 years after it was purchased to the nearest hundred dollar?

the value after 17 years is $3400

Step-by-step explanation:

We would apply the formula,

y = ab^t

Where

a represents the initial amount of the car.

t represents the depreciation time.

From the information given

a = 36000

t = 5 years

Since after 5 years, the value depreciates by 0.5, then

y = 0.5 × 36000 = 18000

Therefore

18000 = 36000 × b^5

Dividing through by 36000, it becomes

0.5 = b^5

Raising both sides of the equation by 1/5, it becomes

0.5^(1/5) = b^5/5

b = 0.871

The equation becomes

y = 36000(0.871)^t

After 17 years, the value of the car would be

y = 36000(0.871)^17

y = $3440

y = $3400 to the nearest hundred dollar

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

the 3rd on is correct

step-by-step explanation: