A set of data with 100 observations has a mean of 267. There are six outliers in the data set, which have a mean of 688. If the six outliers are removed, what

Mean of remaining

94 observation= 240.1277

Approximately = 240

Step-by-step explanation:

First the mean of the data with 100 observation is 267, so the summation of the set of data is equall to 267*100= 26700

Now we have six outliers with mean of 688, so total summation of the outliers = 688*6 = 4128

The mean of the remaining set of data with (100-6)= 94 observation is

(26700-4128)/94= 22572/94

Mean of 94 observation= 240.1277

Approximately = 240

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )