2. A plane traveled from California and back. It took one hour longer on the way out than it
did on the way back. The plane's average speed out was 300 mph. The average speed on the
way back was 350 mph. How many hours did the trip out take?
O A. 13 hours
B. 7 hours
O C. 8 hours
OD. 6 hours

Option D is the correct answer.

Step-by-step explanation:

the time out.

Time taken for back = t-1

We have plane's average speed out was 300 mph and average speed on the way back was 350 mph.

That is

Dividing both equations

Time taken for back = t-1 = 7-1 = 6 hours.

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the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

2

step-by-step explanation: