Consider the following data set which relates the hemoglobin levels h (kg/dL) of workers and the altitude a (km) above the sea level that the workers exposed over years:

a 0.32 0.64 1.28 1.60
h 1.15 1.10 1.05 0.95

In the regression model h = c1e^-c2a, the constant c2 is found as c2 = 0.1315. Assuming the hemoglobin concentration for the residents at the highest permanently tolerable altitude of the atmosphere is the 1/1000th of the hemoglobin concentration for the residents at sea level, compute the highest permanently tolerable altitude in kilometers.

The highest permanently tolerable altitude is 52.53 km.

Step-by-step explanation:

We have to calculate the maximum altitude that the residents/workers can tolerate.

This altitude is at which the hemoglobin conventration is 0.001 of the concentration at sea level.

We can express that as:

The highest permanently tolerable altitude is 52.53 km.

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step-by-step explanation:

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(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240