Lines g, h, and k are parallel. That means they have the same slope. Each of these lines has a slope of 1. Enter numbers to complete an equation for each line.

Step-by-step explanation:

Here, given:

The lines g, h and k are given to be parallel.

Also, each of the line has a  slope  = 1

Now, as graph is missing.

Using the needed graph, find the y - intercepts ( a point where x = 0) in the graphs.

Let us assume, the y intercept for  g = a

Let us assume, the y intercept for  h = b

Let us assume, the y intercept for  k = c

Now, by SLOPE INTERCEPT form:  y = m x  +  C  : m = slope. C- y intercept

So, the equation of these three lines is given as:

Line equation of g :    y  = 1 x  + a

Line equation of h :    y  = 1 x  + b

Line equation of k :    y  = 1 x  + c

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2