Daniel had $25 to spend at the fair. If the admission to the fair is $4 and the rides cost $1.50 each, what is the greatest number of rides Daniel can go on? A. Write an inequality that represents Daniel's situation. B. How many rides can Daniel go on?. Justify your answer.

1.5*(Max. no. of rides) + 4 = 25

Max. No. of rides = 14

Step-by-step explanation:

The equation can be written as:

(Max. No. of Rides)(Cost of each ride) + Admission Cost = Total Money at Hand

Let,

'R' be the maximum no. of rides Daniel can go on.

Cost of each ride=$1.5

Admission Cost=$4

Total Money at Hand=$25

Substituting values in above equation we get,

Hence, the max. no. of rides Daniel can take is 14.

The inequality equation can be written as:

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.