Use the quadratic formula to find the solutions for
-x^2 - 5x + 12 = 0

x1=-6.772

x2=1.772

Step-by-step explanation:

-x²-5x+12=0

For the general quadratic form: ax²+bx+c=0, the roots are found with formula:

x1,2=(-b +- sqrt(delta))/(2a)

where delta=b²-4ac.

In our case: a=-1, b=-5, c=12

delta=b²-4ac=(-5)²-4(-1)×12=25+48=73

Sqrt(delta)=sqrt(73)=8.544

x1,2=(5 +- 8.544)/(-2)

x1=-(5+8.544)/2=-13.544/2=-6.772

x2=-(5-8.544)/2=3.544/2=1.772

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

i believe that the answer is

b. y-1=-2(x-4)

hope this !