Use polar coordinates to find the limit. [If (r, θ) are polar coordinates of the point (x, y) with r ≥ 0, note that r → 0+ as (x, y) → (0, 0).] (If an answer does not exist, enter DNE.) lim (x, y)→(0, 0) x6 + y3 x2 + y2

where in the last equality, the denominators of both limands are equal, but in the numerator we use the fact that and . In other words, the numerator is bounded above and below by polynomials in . The numerator has degree higher than that of the denominator, so as , so is the limit equal to 0.

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: