Factor completely 2x^2+21x-11
Can I get step by step instructions for this please?

(x+11)(2x-1)

Step-by-step explanation:

First, you want to look at the quadratic. Clearly it doesn't have any GCF. So what you have to do is multiply 2 to the c value: -11. To get:

Second, you find the factors of -22 that add to 21.

I've isolated the factors to be 22 and -1. So like a regular quadratic you solve and "plug" it in. (x+22)(x-1)

Third, you can't forget about the multiplied 2. You have to distribute it by plugging the 2 back in front of x in both parenthesis groups. (2x+22)(2x-1)

As you can see, 2x+22 can be simplified. so you simplify, and you get(x+11)(2x-1).

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

x=half

step-by-step explanation: