Find an equation for the line parallel to 4y+8x=8 and goes through the point (-8, 1) Write your answer in the form y= mx+b

y = -2x - 15

Step-by-step explanation:

We are asked to find the equation of a line parallel to 4y + 8x = 8

Step 1: find the slope

4y + 8x = 8

4y = 8 - 8x

Divide both sides by 4, to get y

4y/4 =( 8 - 8x)/4

y = (8 - 8x)/4

We can rewrite it

y =( -8x + 8)/4

y = mx + c

Separate it to get the slope

y = -8x/4 + 8/4

y = -2x + 2

Slope m = -2

Step 2: using

y - y_1 = m(x - x_1)

Substitute m = -2 into the equation

y - y_1 = -2(x - x_1)

Step 3: substitute the point into the equation

( -8,1)

x_1 = -8

y_1= 1

y - 1 = -2(x - (-8)

y - 1 = -2(x + 8)

Open the bracket

y - 1 = -2x - 16

y = -2x - 16 + 1

y = -2x - 15

Therefore the equation of the line is

y = -2x - 15