Find the 12th term of the geometric sequence 2, -8,32, ...

-8388607

Step-by-step explanation:

a = 2

r = -8/2 = -4

12th term = (2)×(-4)¹¹

= -8388608

Step-by-step explanation:

hello :

the n-ieme term is : An=A1×r^(n-1)

A1 the first term       r : the common ratio

in this exercice : A1 =2       r = 32/-8=-8/2 = - 4         n = 12

A12=2×(-4)^(12-1) = -2×4^11     because :   ((-4)^(11)= - 4^11

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.