Abaseball is thrown with a vertical velocity of 50 ft/s from an initial height of 6 ft. the height h in feet of the baseball can be modeled by h(t) = -16t2 + 50t + 6, where t is the time in seconds since the ball was thrown. it takes the ball approximately
seconds to reach its maximum height. (round to the nearest tenth of a second and enter only the number.)

to the nearest foot, what is the maximum height that the ball reaches? (enter only the number.)

a player hits a foul ball with an initial vertical velocity of 70 ft/s and an initial height of 5 feet. the maximum height reached by the ball is
feet. (round to the nearest foot and enter only the number.)

i need the answers.