Inside the square ABCD, side 15 cm, the point M is considered, so that the triangle ABM is equilateral. Show that:

a) The area of ABCD = 225 cm square,

b) The triangle MDC is isosceles,

c) PLEASE HELP ME!

a) 15*15=225 that is the area

b)see picture that I drew (sorry I have terrible drawing skills on a computer) but in a an isosceles triangle the two legs are congruent and the base is not when you cut a square diagonally as you have done this one the base will not be the same as the other two legs.

Step-by-step explanation:

Step-by-step explanation:

a) area of square: 15 x 15 = 225 cm²

b) The steps are illustrated in the picture.

ΔADM ≅ ΔBCM (sas)

DM = CM

ΔMDC is isoceles

the answer is 5636.7

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi