One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second container is 55% larger than the first, and the two containers are emptied into a third container. What percent of acid is the third container?

Therefore the third container contains   = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

  cubic unit.

 cubic unit.

The amount of acid in first container is

 cubic unit.

 cubic unit.

The amount of acid in second container is

cubic unit.

cubic unit.

Total amount of acid cubic unit.

                                    cubic unit.

                                   cubic unit.

Total volume of mixture cubic unit.

                                        cubic unit.

                                         cubic unit.

The amount of acid in the mixture is

Therefore the third container contains    acid.

this is false ^.^ lol

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11