For a fundraiser, the sixth grade band members must average $60 in candy sales. Fifteen students have sold a total of $840.00. How much will the last student have to sell to raise the mean to $60 per student

$120

Step-by-step explanation:

The sixth grade band members has a total of sixteen members, as the problem says that fifteen have sold a certain amount, and how much will the LAST student have to sell.

As the mean is $60 per student, and we have 16 students, the total raised need to be 60*16 = $960

The first fifteen students have earned $840, so to reach $960, the last student will have to raise 960 - 840 = $120, so the mean will be $60 per student.

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x