For what value of \\(x\\) is the function \\(\\frac{1}{x-2}\\) not defined?

The function is not defined for x=2

Step-by-step explanation:

we have

we know that

In a quotient the denominator cannot be equal to zero

so

equate the denominator to zero to find the value of x

solve for x

therefore

The function is not defined for x=2

x = 2.

Step-by-step explanation:

1 / (x - 2)  is not defined if x = 2, because that would make the denominator = 0.

1/0 is not defined.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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