A museum opened at 8:00 a. M. In the first hour, 350 prople purchased admission tickets. In the second hour, 20% more people purchased admission ticks than in the first hour. Each admisssion tickets cost $17.50. What was the total amount of money paid for all the tickets purchased in the first tow hours?

$13,475

Step-by-step explanation:

In the first hour:

350 people purchased admission tickets.

In the second hour:

20% MORE people purchased admission tickets.

Implication is, 20% of 350

= 20/ 100 * 350

simplifying that:

=2 * 35

=70

Therefore, 2nd hour purchase:

= 350 + 70

= 420 admission tickets.

TO GET THE TOTAL COST OF ADMISSION TICKETS BOUGHT, we Multiply the value of each admission tickets by the numbers of tickets bought.

1st hour Purchase = 350 * $17.50

= $6,125

2nd hour purchase = 420 * $17.50

= $7,350

Total amount of money paid for all the tickets purchased in the first two hours:

=$6125 + $7350

=$13,475

Enjoy! Maths is fun

isi

step-by-step explanation:

use that smart brain

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)