Find Y.
Round to the nearest tenth.
Y= ? degrees

Angle Y equals 58.9 degrees (to the nearest tenth)

Step-by-step explanation: The triangle given in the question already has all three sides provided, while none of the angles has been given. We can apply the cosine rule which states that,

c^2 = a^2 + b^2 - 2ab CosC

Where C is the reference angle, we shall replace this with a new label, Y to suit our question. Hence our Cosine Rule can be re-written as ;

y^2 = x^2 + z^2 -2xz CosY

20^2 = 22^2 + 18^2 -(2{22 x 18}CosY)

400 = 484 + 324 - (2{396} CosY)

400 = 808 - (792 CosY)

Subtract 808 from both sides of the equation

-408 = -792CosY

Divide both sides of the equation by -792

-408/-792 = CosY

0.5151 = CosY

By use of calculator or table of values, 0.5151 equals 58.9958

Approximately to the nearest tenth,

Y = 58.9 degrees

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1