Can someone check if this is right and correct me if it’s not?

No. it is not tangent to the circle ⇒ A

Step-by-step explanation:

In any circle a tangent and a diameter are perpendicular at one end of the diameter

In the attached figure

∵ The line segment drawn from point A is passing through

   the center of the circle

∴ This line segment is a diameter of the circle

∵ If AB is a tangent to the circle at point A

- That means the diameter and the tangent meet each other

  at point A (one end of the diameter)

∴ AB and the diameter are perpendicular at point A

∴ m∠A = 90°

Now let us check if the lengths of the triangle formed a right angle triangle or not by using the inverse of Pythagoras Theorem

In a triangle if the square of the longest side is equal to the sum of the squares of the other two sides, then the triangle is a right triangle at the vertex which opposite to the longest side

∵ 17 is the longest side in the triangle

∵ The other two sides are 10.2 units and 6.8 units

∵ (17)² = 289

∵ (10.2)² + (6.8)² = 150.28

∴ (17)² ≠ (10.2)² + (6.8)²

∴ The triangle can not be a right triangle because the square

    of the longest side is not equal to the sum of the squares of the

    other two sides

∵ ∠A is opposite to the longest side

∴ m∠A ≠ 90°

∴ Line AB is not perpendicular to the diameter at A

∴ Line AB is not a tangent to the circle

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g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)