A combined total of 39000 is invested in two bonds that pay 5% and 6.5% simple interest. The annual interest is 235500 how much is invested in each bond?

$12000 at 5%

$27000 at 6.5%.

Step-by-step explanation:

Let x represent amount invested at 5% and y represent amount invested at 6.5%.

We have been given that a combined total of 39000 is invested in two bonds. We can represent this information in an equation as:

We are also told that the annual interest rate is 2355.00. We can represent this information in an equation as:

Upon substituting equation (1) in equation (2), we will get:

Therefore, an amount of $12,000 is invested at 5%.

Upon substituting in equation (1), we will get:

Therefore, an amount of $27,000 is invested at 6.5%.

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like:

step-by-step explanation: