1. Suppose that the average outstanding credit balance for young couples is $650 with a standard deviation of $420. In an SRS of 100 couples, what is the probability that the mean outstanding credit balance exceeds $700?

11.70% probability that the mean outstanding credit balance exceeds $700

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation , the sample means with size n of at least 30 can be approximated to a normal distribution with mean and standard deviation

In this problem, we have that:

In an SRS of 100 couples, what is the probability that the mean outstanding credit balance exceeds $700?

This is 1 subtracted by the pvalue of Z when X = 700. So

By the Central Limit Theorem

has a pvalue of 0.8830

1 - 0.8830 = 0.1170

11.70% probability that the mean outstanding credit balance exceeds $700

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

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