Lily bought 6 skirts and 5 coats for a total of $452.62. if lily sister bought 3 skirts and 5 coats for $289.36, what was the price of one coat? $(round to the nearest cent)

$26.02

Step-by-step explanation:

Let the price of a skirt be A and that of coat be B

Iilly bought 6 skirts and 5 coats for a total of $452.62

That’s

6A + 5B = 452.62

Also, Lilly’s sister bought 3 skirts and 5 coats for $289.36

That’s

3A + 5B = 289.36

We now have two equations

1 . 6A + 5B = 452.62

2. 3A + 5B = 289.36

Subtract equation two from equation one

We have

3A = 163.26

Divide both sides by 3

3A/3 = 163.26/3

A = 54.42

A = $54.42

Now substitute 54.42 for A in either equations to get B the price of a coat

Using equation one, we have

6A + 5B = 452.62

6 x 54.42 + 5B = 456.62

326.52 + 5B = 456.62

Subtract 326.52 from both sides

326.52 - 326.52 + 5B = 456.62 - 326.52

5B = 130.1

Divide both sides by 5

5B/5 = 130.1/5

B = 26.02

= $26.02

A coat cost $26.02

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61